Delay Budget Three-Row Scan - Electronic Circuits XII: Clocks, Latches, and Timing Closure Step by Step

The same delay chain passes, touches the boundary, then fails as period tightens. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A ten-second period leaves two seconds of delay margin

The stage delays stay 1, 2, and 3 seconds. Period 10 seconds gives budget 8 seconds and slack 2 s.

10+(-2)=8\ \text{s},\quad 8+(-6)=2\ \text{s}

An eight-second period uses the whole delay budget

The stage delays stay 1, 2, and 3 seconds. Period 8 seconds gives budget 6 seconds and slack 0 s.

8+(-2)=6\ \text{s},\quad 6+(-6)=0\ \text{s}

A seven-second period makes the same path fail

The stage delays stay 1, 2, and 3 seconds. Period 7 seconds gives budget 5 seconds and slack -1 s.

7+(-2)=5\ \text{s},\quad 5+(-6)=-1\ \text{s}