The final sharing voltage moves when source capacitance or source voltage changes. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Final voltage divides conserved charge by total capacitance

The final voltage is downstream of both source capacitors; changing either source capacitance or source voltage changes the quotient.

Vf=QtotalCtotal=24 C/6 FV_f={Q_{\text{total}}\over C_{\text{total}}}=24\ \text{C}/6\ \text{F}
Charge-sharing quotientFinal voltage is computed from total charge and total capacitance.Ca 4 FVa 6 VQtot 24 CVf 4 V

Capacitance and voltage changes enter the same quotient

The table separates changing source capacitance from changing source voltage so the final-voltage quotient is visible both ways.

scanCaVaQtotalVfCa changes2 F6 V12 C3 VCa changes4 F6 V24 C4 VCa changes6 F6 V36 C92 VVa changes4 F3 V12 C2 VVa changes4 F6 V24 C4 VVa changes4 F9 V36 C6 V\begin{array}{c|c|c|c|c}\text{scan}&C_a&V_a&Q_{\text{total}}&V_f\\C_a\ \text{changes}&2\ \text{F}&6\ \text{V}&12\ \text{C}&3\ \text{V}\\C_a\ \text{changes}&4\ \text{F}&6\ \text{V}&24\ \text{C}&4\ \text{V}\\C_a\ \text{changes}&6\ \text{F}&6\ \text{V}&36\ \text{C}&\tfrac{9}{2}\ \text{V}\\V_a\ \text{changes}&4\ \text{F}&3\ \text{V}&12\ \text{C}&2\ \text{V}\\V_a\ \text{changes}&4\ \text{F}&6\ \text{V}&24\ \text{C}&4\ \text{V}\\V_a\ \text{changes}&4\ \text{F}&9\ \text{V}&36\ \text{C}&6\ \text{V}\\\end{array}

The final sharing row is a quotient of checked totals

This row is not a lossless-energy claim; it is only the charge-conservation voltage row.

24 C/6 F=4 V24\ \text{C}/6\ \text{F}=4\ \text{V}
Charge-sharing quotientFinal voltage is computed from total charge and total capacitance.Ca 4 FVa 6 VQtot 24 CVf 4 V