Secondary load resistance becomes a primary-side current budget. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Load resistance row 1

Transformer voltage ratio stays fixed. Secondary load 12 ohm gives secondary current 1/2 A and primary load current 1/4 A against a 1/2 A budget, so margin is 1/4 A.

m=14 Apassm=\tfrac{1}{4}\ \text{A}\quad\text{pass}
Primary-current budget boundaryThe current budget is downstream of the load reflection.Np 4Ns 2Vp 12 VVs 6 VIp 1/4 AIs 1/2 APp 3 WPs 3 WRload 12 ohmRref 48 ohmVp 12 VVs 6 VIp(load) 1/4 AIs 1/2 APp 3 WPs 3 Wclaim loaded reflected current

Load resistance row 2

Transformer voltage ratio stays fixed. Secondary load 6 ohm gives secondary current 1 A and primary load current 1/2 A against a 1/2 A budget, so margin is 0 A.

m=0 Apassm=0\ \text{A}\quad\text{pass}
Primary-current budget boundaryThe current budget is downstream of the load reflection.Np 4Ns 2Vp 12 VVs 6 VIp 1/2 AIs 1 APp 6 WPs 6 WRload 6 ohmRref 24 ohmVp 12 VVs 6 VIp(load) 1/2 AIs 1 APp 6 WPs 6 Wclaim loaded reflected current

Load resistance row 3

Transformer voltage ratio stays fixed. Secondary load 3 ohm gives secondary current 2 A and primary load current 1 A against a 1/2 A budget, so margin is negative 1/2 A.

m=12 Afailm=\tfrac{-1}{2}\ \text{A}\quad\text{fail}
Primary-current budget boundaryThe current budget is downstream of the load reflection.Np 4Ns 2Vp 12 VVs 6 VIp 1 AIs 2 APp 12 WPs 12 WRload 3 ohmRref 12 ohmVp 12 VVs 6 VIp(load) 1 AIs 2 APp 12 WPs 12 Wclaim loaded reflected current