Transformer turns are carried through rectifier loss and reservoir valley acceptance. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Secondary turns 2 sets reservoir margin

Primary source stays 24 V with 6 primary turns. Secondary turns 2 produce valley 4 V against the 8 V minimum, so margin is negative 4 V.

4 V8 V=4 Vfail4\ \text{V}\mathbin{-}8\ \text{V}=-4\ \text{V}\Rightarrow\text{fail}
Transformer-to-valley boundaryThe turns choice is carried through rectifier and reservoir.Np 6 turnsNs 2 turnsVp 24 VVs 8 VVsrc 8 VVd 1 VnD 2 diodesVout 6 VIload 2 Adt 3 sC 3 FdV 2 VVmin 8 Vgate fail

Secondary turns 3 sets reservoir margin

Primary source stays 24 V with 6 primary turns. Secondary turns 3 produce valley 8 V against the 8 V minimum, so margin is 0 V.

8 V8 V=0 Vpass8\ \text{V}\mathbin{-}8\ \text{V}=0\ \text{V}\Rightarrow\text{pass}
Transformer-to-valley boundaryThe turns choice is carried through rectifier and reservoir.Np 6 turnsNs 3 turnsVp 24 VVs 12 VVsrc 12 VVd 1 VnD 2 diodesVout 10 VIload 2 Adt 3 sC 3 FdV 2 VVmin 8 Vgate pass

Secondary turns 4 sets reservoir margin

Primary source stays 24 V with 6 primary turns. Secondary turns 4 produce valley 12 V against the 8 V minimum, so margin is 4 V.

12 V8 V=4 Vpass12\ \text{V}\mathbin{-}8\ \text{V}=4\ \text{V}\Rightarrow\text{pass}
Transformer-to-valley boundaryThe turns choice is carried through rectifier and reservoir.Np 6 turnsNs 4 turnsVp 24 VVs 16 VVsrc 16 VVd 1 VnD 2 diodesVout 14 VIload 2 Adt 3 sC 3 FdV 2 VVmin 8 Vgate pass