Load current turns the same voltage drop into a waste-power limit check. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

1 A waste row

Input and output stay 7 V and 5 V. Load current 1 A makes waste 2 W against a 4 W budget, so margin is 2 W.

Pw=2 W,m=2 WP_w=2\ \text{W},\quad m=2\ \text{W}
Regulator waste-current boundaryLoad current moves the thermal waste claim.Vin 7 VVout 5 VVh 1 VVreq 6 Vgate pass

2 A waste row

Input and output stay 7 V and 5 V. Load current 2 A makes waste 4 W against a 4 W budget, so margin is 0 W.

Pw=4 W,m=0 WP_w=4\ \text{W},\quad m=0\ \text{W}
Regulator waste-current boundaryLoad current moves the thermal waste claim.Vin 7 VVout 5 VVh 1 VVreq 6 Vgate pass

3 A waste row

Input and output stay 7 V and 5 V. Load current 3 A makes waste 6 W against a 4 W budget, so margin is negative 2 W.

Pw=6 W,m=2 WP_w=6\ \text{W},\quad m=-2\ \text{W}
Regulator waste-current boundaryLoad current moves the thermal waste claim.Vin 7 VVout 5 VVh 1 VVreq 6 Vgate pass