With input fixed, base resistance changes drive and moves the inverter output. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Sixteen ohms leaves the output near the top

Input stays 5 V while base resistance 16 ohm sets collector current 3/4 A and output 9 V, and checked state MIDDLE.

RB=16 ΩVout=9 VR_B=16\ \Omega\Rightarrow V_\text{out}=9\ \text{V}
Inverter base-resistance scanThe same input is checked through different base resistors.input 5 Vdrop 1 Vbase 1/4 Adrive 3/4 Aload 3 Acollector 3/4 Aoutput 9 VactiveMIDDLE

Eight ohms pulls the output to the middle

Input stays 5 V while base resistance 8 ohm sets collector current 3/2 A and output 6 V, and checked state MIDDLE.

RB=8 ΩVout=6 VR_B=8\ \Omega\Rightarrow V_\text{out}=6\ \text{V}
Inverter base-resistance scanThe same input is checked through different base resistors.input 5 Vdrop 1 Vbase 1/2 Adrive 3/2 Aload 3 Acollector 3/2 Aoutput 6 VactiveMIDDLE

Four ohms reaches the low output floor

Input stays 5 V while base resistance 4 ohm sets collector current 3 A and output 0 V, and checked state LOW.

RB=4 ΩVout=0 VR_B=4\ \Omega\Rightarrow V_\text{out}=0\ \text{V}
Inverter base-resistance scanThe same input is checked through different base resistors.output 0 Vinput 5 Vdrop 1 Vbase 1 Adrive 3 Aload 3 Acollector 3 AsaturationLOW