Trees
Level-Order Traversal
Visit a tree breadth-first with a queue.
Algorithm
The canonical tree is 4(2(1,3),6(5,7)), so this Bash DSA
implementation can be compared directly with the rest of the DSA track.
level order
Level-order traversal uses a queue to visit shallower nodes first.
Basic Implementation
basic.sh
Replay: real traced execution (multi-file project)
#!/usr/bin/env bash
declare -A val left right
new_node() { local id=$1 value=$2 l=${3:-0} r=${4:-0}; val[$id]=$value; left[$id]=$l; right[$id]=$r; }
render() {
local id=$1
if [[ "$id" == "0" || -z "$id" ]]; then printf "_"; return; fi
if [[ "${left[$id]}" == "0" && "${right[$id]}" == "0" ]]; then printf "%s" "${val[$id]}"; return; fi
printf "%s(" "${val[$id]}"; render "${left[$id]}"; printf ","; render "${right[$id]}"; printf ")"
}
sample_tree() {
new_node 1 1; new_node 3 3; new_node 2 2 1 3
new_node 5 5; new_node 7 7; new_node 6 6 5 7
new_node 4 4 2 6
}
list_string() {
local joined=""
for value in "$@"; do
[[ -n "$joined" ]] && joined+=", "
joined+="$value"
done
printf '[%s]' "$joined"
}
sample_tree
queue=(4); output=(); front=0
while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); done
list_string "${output[@]}"; echo
tree ← 4(2(1,3),6(5,7)), queue ← [4]
1#!/usr/bin/env bash2declare -A val left rightvalues this step4(2(1,3),6(5,7))tree[4]queueoutput ← [4], queue ← [2, 6]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4]output[2, 6]queue4dequeuedoutput ← [4, 2], queue ← [6, 1, 3]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2]output[6, 1, 3]queue2dequeuedoutput ← [4, 2, 6], queue ← [1, 3, 5, 7]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2, 6]output[1, 3, 5, 7]queue6dequeuedoutput ← [4, 2, 6, 1], queue ← [3, 5, 7]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2, 6, 1]output[3, 5, 7]queue1dequeuedoutput ← [4, 2, 6, 1, 3], queue ← [5, 7]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2, 6, 1, 3]output[5, 7]queue3dequeuedoutput ← [4, 2, 6, 1, 3, 5], queue ← [7]
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2, 6, 1, 3, 5]output[7]queue5dequeuedoutput ← [4, 2, 6, 1, 3, 5, 7], queue ← []
23sample_tree24queue=(4); output=(); front=025while (( front < ${#queue[@]} )); do id=${queue[$front]}; ((front++)); output+=("${val[$id]}"); [[ "${left[$id]}" != "0" ]] && queue+=("${left[$id]}"); [[ "${right[$id]}" != "0" ]] && queue+=("${right[$id]}"); donevalues this step[4, 2, 6, 1, 3, 5, 7]output[]queue7dequeuedif [[ "$id" == "0" || -z "$id" ]]; then printf "_"; return; fi
5local id=$16if [[ "$id" == "0" || -z "$id" ]]; then printf "_"; return; fi7if [[ "${left[$id]}" == "0" && "${right[$id]}" == "0" ]]; then printf "%s" "${val[$id]}"; return; fivalues this step[4, 2, 6, 1, 3, 5, 7]output
Complexity
- Time: O(n)
- Space: O(w) queue space
Implementation notes
- Render tree structure explicitly instead of printing node objects.
- The replay highlights the node, traversal state, queue, path, or search cursor that changes at each step.