Visit a start vertex, then recurse into its first unvisited neighbour all the way down before backtracking. A visited set prevents revisiting, and neighbour insertion order fixes the visit sequence.

Algorithm

On the canonical 6-vertex graph from graph-adjacency-list, starting at vertex 1, the deterministic visit order is [1, 2, 4, 3, 5, 6]. Calls unwind 6 -> 5 -> 4 -> 3 -> 2 -> 1 after all vertices are visited.

Basic Implementation

basic.scala
import scala.collection.mutable.{HashMap, HashSet, ArrayBuffer}
object Main {
	val adj = HashMap.empty[Int, List[Int]]
	val visited = HashSet.empty[Int]
	val order = ArrayBuffer.empty[Int]
	def dfs(v: Int): Unit = {
		visited += v
		order += v
		for (nb <- adj(v)) {
			if (!visited.contains(nb)) {
				dfs(nb)
			}
		}
	}
	def main(args: Array[String]): Unit = {
		adj(1) = List(2, 3)
		adj(2) = List(1, 4)
		adj(3) = List(1, 4)
		adj(4) = List(2, 3, 5)
		adj(5) = List(4, 6)
		adj(6) = List(5)
		dfs(1)
		println(order.mkString("[", ", ", "]"))
	}
}

Complexity

  • Time: O(V + E)
  • Space: O(V) recursion depth

Implementation notes

  • Scala: a recursive dfs over object-level adj, visited, and order; mkString renders the buffer.
  • The replay shows the current vertex, the visited set, and the running visit order after each entry, matching the lesson spec.
recursive descent Follow one branch to its end, then unwind and try the next neighbour.