Linked Structures
Delete by Value
Find the node before the target value and rewire its next pointer so the target node leaves the chain.
Algorithm
The replay labels nodes by value, such as node(20), and never exposes object
identity or memory addresses. This Rust DSA implementation uses the
same small chain as the rest of the DSA track.
Basic Implementation
basic.rs
struct Node {
value: i32,
next: Option<Box<Node>>,
}
fn node(value: i32, next: Option<Box<Node>>) -> Option<Box<Node>> {
Some(Box::new(Node { value, next }))
}
fn render(head: &Option<Box<Node>>) -> String {
let mut parts: Vec<String> = Vec::new();
let mut cursor = head.as_ref();
while let Some(node) = cursor {
parts.push(node.value.to_string());
cursor = node.next.as_ref();
}
parts.join(" -> ") + " -> null"
}
fn delete_value(head: Option<Box<Node>>, target: i32) -> Option<Box<Node>> {
match head {
Some(mut n) => {
if n.value == target {
n.next
} else {
n.next = delete_value(n.next, target);
Some(n)
}
}
None => None,
}
}
fn main() {
let head = node(10, node(20, node(30, node(40, None))));
let target = 30;
let head = delete_value(head, target);
println!("{}", render(&head));
}
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Keep the explicit node and pointer/reference operations; array shortcuts hide the linked-list state this lesson is meant to replay.
- The final output prints the chain in a deterministic
a -> b -> nullform for cross-language comparison.
predecessor
Deletion needs the node before the one being removed.
rewiring
The predecessor skips the target and points at the target's next node.