Arrays and Iteration
Linear Search
Walk an array once looking for a target value. Return the index of the
first match, or -1 if none. The simplest possible search loop.
Algorithm
Canonical input arr = [4, 7, 1, 9, 3, 8] with target = 9 finishes
after four compares; the matching index is 3.
Basic Implementation
basic.rs
fn linear_search(arr: &[i32], target: i32) -> i32 {
for i in 0..arr.len() {
if arr[i] == target {
return i as i32;
}
}
-1
}
fn main() {
let arr = [4, 7, 1, 9, 3, 8];
let target = 9;
let result = linear_search(&arr, target);
println!("{}", result);
}
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Rust: explicit
for i in 0..arr.len()with an earlyreturn i as i32the momentarr[i] == target. The standardarr.iter().position(...)would hide the walk the lesson is teaching. - Function signature
fn linear_search(arr: &[i32], target: i32) -> i32documents the slice contract; the-1sentinel mirrors the language-neutral spec rather than returningOption<usize>. - The replay shows the running index, the element being checked, and a
matchindicator on each frame.
early exit
Return the index the moment `arr[i]` equals the target. Walking past it would defeat the point.
sentinel return
A no-match walk falls off the loop and returns `-1`.