Force is scanned below, at, and above a finite impulse floor. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
Force is scanned through a finite impulse floor
The time window stays 4 s while force is 2 N. The asserted impulse is 8 kilogram meters per second which is below the 12 kilogram meters per second impulse floor.
J=Ft=2⋅4=8kgm/s
Force is scanned through a finite impulse floor
The time window stays 4 s while force is 3 N. The asserted impulse is 12 kilogram meters per second which is at the 12 kilogram meters per second impulse floor.
J=Ft=3⋅4=12kgm/s
Force is scanned through a finite impulse floor
The time window stays 4 s while force is 4 N. The asserted impulse is 16 kilogram meters per second which is above the 12 kilogram meters per second impulse floor.