Three cart speeds are checked against the speed-squared column so kinetic energy cannot be read as a merely linear speed rule.
Example
Kinetic energy is checked across three exact speed cases, with the speed-squared column exposed so the square cannot hide. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
Audit the square, not just the speed
Keep the mass fixed at 2 kg. The whole speed quantity is squared, so the table must grow by speed squared, not by speed alone.
KE=21mv2
First exact speed case
At 4 m/s, the speed-squared column is 16. With the fixed mass, the kinetic energy closes at 16 J.
KE=212kg(4m/s)2=16J=16J
Second exact speed case
At 6 m/s, the speed-squared column is 36. The energy follows that square and closes at 36 J.
KE=212kg(6m/s)2=36J=36J
Third exact speed case
At 8 m/s, the speed-squared column is 64. The arrow is twice the first arrow, but the energy is four times the first energy.
KE=212kg(8m/s)2=64J=64J
The three rows expose the square
Scan down the rows. The speed values grow steadily, but the energy tracks the speed-squared column exactly.
v4m/s6m/s8m/sspeed squared163664KE16J36J64J
mechanicsWith a fixed 2 kg mass, the speed-squared values 16, 36, and 64 close exactly to 16 J, 36 J, and 64 J.