Three frictionless drops balance gravitational potential energy against bottom kinetic energy, row by row.
Example
Three frictionless drops balance gravitational potential energy against bottom kinetic energy, row by row. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.
highlighted = computed this step
Audit height against bottom speed
Use the same mass and gravity each time. The potential energy from height must equal the bottom kinetic energy on the frictionless track.
mgh=21mv2
First drop closes
A drop of 5 m stores 100 J. The bottom speed 10 m/s gives the same kinetic energy.
mgh=2kg⋅10m/s2⋅5m=100J=212kg(10m/s)2=100J
Second drop closes
A drop of 20 m stores 400 J. The bottom speed 20 m/s closes the same ledger.
mgh=2kg⋅10m/s2⋅20m=400J=212kg(20m/s)2=400J
Third drop closes
A drop of 45 m stores 900 J. The bottom speed 30 m/s matches that larger energy.
mgh=2kg⋅10m/s2⋅45m=900J=212kg(30m/s)2=900J
Each row balances potential and kinetic energy
The height column makes potential energy. The speed column makes kinetic energy. The two energy columns match row by row.