Balanced primary reset rows can still exceed a secondary pulse ceiling. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Reset row 1

Primary reset is balanced first. Secondary turns 1 give secondary on-pulse 3 V against a 6 V ceiling, so margin is 3 V.

m=3 Vpassm=3\ \text{V}\quad\text{pass}
Secondary reset-pulse boundaryThe secondary pulse is downstream of accepted primary balance.Vs=3 Vceiling=6 Vmargin=3 Vpass

Reset row 2

Primary reset is balanced first. Secondary turns 2 give secondary on-pulse 6 V against a 6 V ceiling, so margin is 0 V.

m=0 Vpassm=0\ \text{V}\quad\text{pass}
Secondary reset-pulse boundaryThe secondary pulse is downstream of accepted primary balance.Vs=6 Vceiling=6 Vmargin=0 Vpass

Reset row 3

Primary reset is balanced first. Secondary turns 3 give secondary on-pulse 9 V against a 6 V ceiling, so margin is negative 3 V.

m=3 Vfailm=-3\ \text{V}\quad\text{fail}
Secondary reset-pulse boundaryThe secondary pulse is downstream of accepted primary balance.Vs=9 Vceiling=6 Vmargin=-3 Vfail