A regulator-waste-is-input-minus-output scan closes a linear-regulator power ledger by splitting input power into useful load power and dissipated waste. The exact rows use the stated 7 V input, 5 V output, and load currents, so the voltage difference is spent at the same current. Real regulators have dropout curves, ripple, temperature limits, package thermal resistance, tolerance stacks, finite precision, and measurement uncertainty.

The input power budget closes as load plus waste. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A linear regulator spends the voltage difference

The input minimum is 7 V while the output is 5 V. The difference is dissipated at the same load current.

Pwaste=(Vin−Vout)IP_{\text{waste}}=(V_{\text{in}}-V_{\text{out}})I
Waste split setupInput, load, and waste power share one current.Vin 7 VVout 5 VVh 1 VVreq 6 Vgate pass

Input power closes as load plus waste in every row

The voltage difference stays fixed, so load power and waste power climb together with current.

IPinPloadPwaste1 A7 W5 W2 W2 A14 W10 W4 W3 A21 W15 W6 W\begin{array}{c|c|c|c}I&P_{\text{in}}&P_{\text{load}}&P_{\text{waste}}\\1\ \text{A}&7\ \text{W}&5\ \text{W}&2\ \text{W}\\2\ \text{A}&14\ \text{W}&10\ \text{W}&4\ \text{W}\\3\ \text{A}&21\ \text{W}&15\ \text{W}&6\ \text{W}\\\end{array}

Input power splits into load power plus waste

A linear training regulator spends the voltage difference at the same current.

7 V⋅2 A=14 W=10 W+4 W7\ \text{V}\cdot2\ \text{A}=14\ \text{W}=10\ \text{W}+4\ \text{W}
Regulator waste budgetInput power closes as load plus waste.Vin 7 VVout 5 VVh 1 VVreq 6 Vgate pass