Same-phase source and load impedances divide voltage by exact load share. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Equal source and load split the voltage

Source impedance 2 ohms and load impedance 2 ohms put 1/2 of the voltage on the load.

1624=816\cdot {2\over 4}=8
Same phase divider scan rowThe load marker equals the checked voltage share.2 ohm2 ohmV8 V+-8 V+-8 Vsame-phase

A larger load takes three quarters

Load impedance 6 ohms makes the load share 3/4 and output voltage 12.

1668=1216\cdot {6\over 8}=12
Same phase divider scan rowIncreasing the load impedance raises load voltage.2 ohm6 ohmV12 V+-4 V+-12 Vsame-phase

A much larger load keeps seven eighths

Load impedance 14 ohms makes the load share 7/8 and output voltage 14.

161416=1416\cdot {14\over 16}=14
Same phase divider scan rowThe source drop shrinks as the load share grows.2 ohm14 ohmV14 V+-2 V+-14 Vsame-phase