Holding wave speed fixed while magnetic amplitude changes makes E=cB readable. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

One tesla gives six volts per metre

Hold the training speed at 6 metres per second. With magnetic amplitude 1 tesla, the electric amplitude is 6 volts per metre.

E=cB=6 m/s1 T=6 V/mE=cB=6\ \text{m}/\text{s}\cdot1\ \text{T}=6\ \text{V}/\text{m}
Field amplitude scan rowThe checked wave row binds speed, B, and E.speed=6 m/smagneticField=1 TelectricField=6 V/mwavelength=3 mfrequency=2 Hz

Two tesla doubles the electric field

Only the magnetic amplitude changes to 2 tesla. The same speed makes the electric field 12 volts per metre.

E=6 m/s2 T=12 V/mE=6\ \text{m}/\text{s}\cdot2\ \text{T}=12\ \text{V}/\text{m}
Field amplitude scan rowThe B row doubles and E doubles with it.speed=6 m/smagneticField=2 TelectricField=12 V/mwavelength=3 mfrequency=2 Hz

Three tesla makes eighteen volts per metre

The third row changes magnetic amplitude to 3 tesla and closes at 18 volts per metre. Three rows make the proportional relation scannable.

E=6 m/s3 T=18 V/mE=6\ \text{m}/\text{s}\cdot3\ \text{T}=18\ \text{V}/\text{m}
Field amplitude scan rowThe final checked row keeps E over B equal to speed.speed=6 m/smagneticField=3 TelectricField=18 V/mwavelength=3 mfrequency=2 Hz