A shear modulus ledger uses sideways displacement over height. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Shear uses sideways displacement over height

The sideways displacement and height form a dimensionless strain. The shear force and area form shear stress.

x=1 mh=3 mx=1\ \text{m}\qquad h=3\ \text{m}
Shear inputsSideways displacement and shear stress are separate.displacementshear stressshearForce=9 Narea=3 m^2displacement=1 mheight=3 mshearStress=3 PashearStrain=1/3modulus=9 Pa

With shear strain fixed, modulus follows stress

The displacement-over-height ratio is fixed in every row. Larger shear force gives larger shear stress and modulus.

FAx/hτG3 N3 m2131 Pa3 Pa6 N3 m2132 Pa6 Pa9 N3 m2133 Pa9 Pa\begin{array}{c|c|c|c|c}F&A&x/h&\tau&G\\3\ \text{N}&3\ \text{m}^{2}&\frac{1}{3}&1\ \text{Pa}&3\ \text{Pa}\\6\ \text{N}&3\ \text{m}^{2}&\frac{1}{3}&2\ \text{Pa}&6\ \text{Pa}\\9\ \text{N}&3\ \text{m}^{2}&\frac{1}{3}&3\ \text{Pa}&9\ \text{Pa}\\\end{array}

Shear modulus uses sideways strain

The shear ledger separates shear stress from sideways strain before computing the modulus.

τ=FA=3 Pa;γ=xh=13;G=τγ=9 Pa\tau=\frac{F}{A}=3\ \text{Pa};\quad \gamma=\frac{x}{h}=\frac{1}{3};\quad G=\frac{\tau}{\gamma}=9\ \text{Pa}
Shear modulus ledgerSideways displacement and height form the shear strain.displacementshear stressshearForce=9 Narea=3 m^2displacement=1 mheight=3 mshearStress=3 PashearStrain=1/3modulus=9 Pa