For the same checked bar stiffness, force scales with extension. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Keep the same bar stiffness before changing extension

Young modulus, area, and length are unchanged. The larger extension is the only input that changes the force.

k=4 N/mΔL=2 mk=4\ \text{N/m}\qquad \Delta L=2\ \text{m}
Same stiffness, larger extensionThe extension vector is larger while stiffness is fixed.forceextensionyoungSource=boundarea=2 m^2length=8 mextension=2 mstiffness=4 N/mforce=8 N

Force follows extension after stiffness is fixed

Read the stiffness column first, then multiply by extension. The middle row is the doubled-extension case.

EALΔLkF16 Pa2 m28 m1 m4 N/m4 N16 Pa2 m28 m2 m4 N/m8 N16 Pa4 m28 m1 m8 N/m8 N\begin{array}{c|c|c|c|c|c}E&A&L&\Delta L&k&F\\16\ \text{Pa}&2\ \text{m}^{2}&8\ \text{m}&1\ \text{m}&4\ \text{N/m}&4\ \text{N}\\16\ \text{Pa}&2\ \text{m}^{2}&8\ \text{m}&2\ \text{m}&4\ \text{N/m}&8\ \text{N}\\16\ \text{Pa}&4\ \text{m}^{2}&8\ \text{m}&1\ \text{m}&8\ \text{N/m}&8\ \text{N}\\\end{array}

Doubling extension doubles the bar force

The stiffness is unchanged, so the checked force follows the extension.

F=kΔL=4 N/m2 m=8 NF=k\Delta L=4\ \text{N/m}\cdot2\ \text{m}=8\ \text{N}
Double-extension bar ledgerThe same bar stiffness is multiplied by a larger extension.forceextensionyoungSource=boundarea=2 m^2length=8 mextension=2 mstiffness=4 N/mforce=8 N