Put the two detector ticks on one ruler: channel A at 3 seconds and channel B at 5 seconds. In this pinned timing rule, the 2 second separation lands exactly on the 2 second coincidence window and is accepted; a real boundary case would still depend on clock calibration, trigger jitter, and binning.

A tick exactly at the window edge is still a coincidence. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Two channel ticks are compared on one clock

Channel A ticks at 3 seconds, and channel B ticks at 5 seconds.

tA=3 s,tB=5 st_A=3\ \text{s},\quad t_B=5\ \text{s}
Coincidence windowTicks are accepted only inside the window.ABW=2 sdt=2 schannelATime=3 schannelBTime=5 swindow=2 sdifference=2 saccepted

The boundary case is accepted

The difference is 2 seconds, matching the 2 second window.

∣tB−tA∣=2≤2|t_B-t_A|=2\le2
Coincidence windowTicks are accepted only inside the window.ABW=2 sdt=2 schannelATime=3 schannelBTime=5 swindow=2 sdifference=2 saccepted