Active Coverage Floor Three-Row Scan - Detector Physics: Timing and Spatial Reconstruction Step by Step

This scan asks whether enough detector length is active to cover a required region. With 2 meter pitch, one active cell gives 2 meters and fails the 4 meter floor, two cells land exactly on the floor, and three cells clear it. Real coverage checks also depend on dead channels, edge gaps, alignment, surveyed dimensions, finite thresholds, and uncertainty.

Active detector length is compared with a coverage floor. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

One active cell is below the coverage floor

Active cells 1 with pitch 2 meters give active length 2 meters.

m=L_{\text{active}}\mathbin{-}L_{\min}=2\mathbin{-}4=-2,\quad\text{fail}

Two active cells exactly meet the floor

Active cells 2 with pitch 2 meters give active length 4 meters.

m=L_{\text{active}}\mathbin{-}L_{\min}=4\mathbin{-}4=0,\quad\text{pass}

Three active cells clear the floor

Active cells 3 with pitch 2 meters give active length 6 meters.

m=L_{\text{active}}\mathbin{-}L_{\min}=6\mathbin{-}4=2,\quad\text{pass}