Shortest Path (Unweighted, via BFS)

BFS explores a graph layer by layer, so the first time it reaches a vertex is along a shortest path. Track dist[v] and parent[v] while exploring, then walk parents back from the target to reconstruct the route.

Algorithm

On the canonical graph from graph-adjacency-list, the shortest path from 1 to 6 is [1, 2, 4, 5, 6] with distance 4. The path is rebuilt from parent: 6 -> 5 -> 4 -> 2 -> 1, reversed.

Basic Implementation

basic.cs

using System;
using System.Collections.Generic;
class Program {
	static void Main() {
		Dictionary<int, List<int>> adj = new Dictionary<int, List<int>>();
		adj[1] = new List<int> { 2, 3 };
		adj[2] = new List<int> { 1, 4 };
		adj[3] = new List<int> { 1, 4 };
		adj[4] = new List<int> { 2, 3, 5 };
		adj[5] = new List<int> { 4, 6 };
		adj[6] = new List<int> { 5 };
		int src = 1;
		int dst = 6;
		Dictionary<int, int> dist = new Dictionary<int, int>();
		Dictionary<int, int> parent = new Dictionary<int, int>();
		dist[src] = 0;
		parent[src] = 0;
		Queue<int> queue = new Queue<int>();
		queue.Enqueue(src);
		while (queue.Count > 0) {
			int v = queue.Dequeue();
			foreach (int nb in adj[v]) {
				if (!dist.ContainsKey(nb)) {
					dist[nb] = dist[v] + 1;
					parent[nb] = v;
					queue.Enqueue(nb);
				}
			}
		}
		List<int> path = new List<int>();
		int node = dst;
		while (node != 0) {
			path.Add(node);
			node = parent[node];
		}
		path.Reverse();
		Console.WriteLine("[" + string.Join(", ", path) + "]");
		Console.WriteLine(dist[dst]);
	}
}

Complexity

Time: O(V + E)
Space: O(V)

Implementation notes

C#: a dist dictionary doubles as the visited check, parent records predecessors (0 marks the source), and a Queue<int> gives FIFO order.
The replay shows dist, parent, and the queue filling in, then the reconstructed path, matching the lesson spec.

layers equal distance BFS order equals distance in an unweighted graph.