Duration Casting

std::chrono duration types make unit conversion explicit.

duration_casting.cpp

#include <chrono>
#include <iostream>

int main() {
    int seconds = ;

    std::chrono::seconds total(seconds);
    auto minutes = std::chrono::duration_cast<std::chrono::minutes>(total);
    int leftover = static_cast<int>((total - minutes).count());

    std::cout << "seconds=" << seconds << std::endl;
    std::cout << "minutes=" << minutes.count() << std::endl;
    std::cout << "leftover=" << leftover << std::endl;
    return 0;
}

#include <chrono>
#include <iostream>

int main() {
    int seconds = ;

    std::chrono::seconds total(seconds);
    auto minutes = std::chrono::duration_cast<std::chrono::minutes>(total);
    int leftover = static_cast<int>((total - minutes).count());

    std::cout << "seconds=" << seconds << std::endl;
    std::cout << "minutes=" << minutes.count() << std::endl;
    std::cout << "leftover=" << leftover << std::endl;
    return 0;
}

#include <chrono>
#include <iostream>

int main() {
    int seconds = ;

    std::chrono::seconds total(seconds);
    auto minutes = std::chrono::duration_cast<std::chrono::minutes>(total);
    int leftover = static_cast<int>((total - minutes).count());

    std::cout << "seconds=" << seconds << std::endl;
    std::cout << "minutes=" << minutes.count() << std::endl;
    std::cout << "leftover=" << leftover << std::endl;
    return 0;
}

duration A duration stores an amount of time together with its unit.

duration_cast `duration_cast` converts a duration to another unit when the conversion may lose detail.