Graphs
Shortest Path (Unweighted, via BFS)
BFS explores a graph layer by layer, so the first time it reaches a vertex
is along a shortest path. Track dist[v] and parent[v] while exploring,
then walk parents back from the target to reconstruct the route.
Algorithm
On the canonical graph from graph-adjacency-list, the shortest path from
1 to 6 is [1, 2, 4, 5, 6] with distance 4. The path is rebuilt from
parent: 6 -> 5 -> 4 -> 2 -> 1, reversed.
Basic Implementation
basic.c
#include <stdio.h>
#define V 7
#define MAX_DEG 4
int main(void) {
int adj[V][MAX_DEG] = {
{-1, -1, -1, -1},
{ 2, 3, -1, -1},
{ 1, 4, -1, -1},
{ 1, 4, -1, -1},
{ 2, 3, 5, -1},
{ 4, 6, -1, -1},
{ 5, -1, -1, -1},
};
int src = 1;
int dst = 6;
int dist[V];
int parent[V];
for (int i = 0; i < V; ++i) {
dist[i] = -1;
parent[i] = 0;
}
dist[src] = 0;
int queue[16];
int qhead = 0;
int qtail = 0;
queue[qtail++] = src;
while (qhead < qtail) {
int v = queue[qhead++];
for (int k = 0; k < MAX_DEG && adj[v][k] != -1; ++k) {
int nb = adj[v][k];
if (dist[nb] == -1) {
dist[nb] = dist[v] + 1;
parent[nb] = v;
queue[qtail++] = nb;
}
}
}
int path[V];
int path_n = 0;
int node = dst;
while (node != 0) {
path[path_n++] = node;
node = parent[node];
}
printf("[");
for (int i = path_n - 1; i >= 0; --i) {
if (i < path_n - 1) printf(", ");
printf("%d", path[i]);
}
printf("]\n");
printf("%d\n", dist[dst]);
return 0;
}
Complexity
- Time: O(V + E)
- Space: O(V)
Implementation notes
- C:
dist[]initialised to-1doubles as the visited check,parent[]records the predecessor (0 marks the source), and a ring of indices over a fixedqueue[]array gives FIFO order. - The replay shows
dist,parent, and the queue filling in, then the reconstructed path, matching the lesson spec.
layers equal distance
BFS order equals distance in an unweighted graph.