A fixed detector address grid needs fewer readout passes when more active channels are available. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

A fixed address grid can need fewer passes

All rows use the same detector address grid and repeat count. Only the active channel count changes, so the pass count becomes the visible tradeoff.

P=NaNcP=\frac{N_a}{N_c}
Indexed throughputIndexed measurements become exact count budgets.indexed readout

Three channel counts expose the inverse factor

More channels do not change the number of addresses. They reduce the number of passes needed per repeat, and scheduled passes then multiply by the fixed repeat count.

NaddrNchanNpassNrepeatNscheduled24382162446212246428\begin{array}{c|c|c|c|c}N_{\text{addr}}&N_{\text{chan}}&N_{\text{pass}}&N_{\text{repeat}}&N_{\text{scheduled}}\\24&3&8&2&16\\24&4&6&2&12\\24&6&4&2&8\\\end{array}
Indexed throughputIndexed measurements become exact count budgets.indexed readout

Scheduled passes close after division

The six-channel row gives 4 passes per repeat. With 2 repeats, the scheduled pass count is 8.

Nscheduled=42=8N_{\text{scheduled}}=4\cdot2=8
Indexed throughputIndexed measurements become exact count budgets.indexed readout