Trees
BST Insert
Insert values into a binary search tree by comparing at each node.
Algorithm
The canonical tree is 4(2(1,3),6(5,7)), so this Swift DSA
implementation can be compared directly with the rest of the DSA track.
binary search tree
Values smaller than a node go left; larger values go right.
Visual walkthrough
Basic Implementation
basic.swift
final class Node {
let value: Int
var left: Node?
var right: Node?
init(_ value: Int, _ left: Node? = nil, _ right: Node? = nil) { self.value = value; self.left = left; self.right = right }
}
func render(_ node: Node?) -> String {
guard let node = node else { return "_" }
if node.left == nil && node.right == nil { return String(node.value) }
return "\(node.value)(\(render(node.left)),\(render(node.right)))"
}
func sampleTree() -> Node {
return Node(4, Node(2, Node(1), Node(3)), Node(6, Node(5), Node(7)))
}
func listString(_ values: [Int]) -> String { return "[" + values.map(String.init).joined(separator: ", ") + "]" }
func insert(_ root: Node?, _ value: Int) -> Node { guard let root = root else { return Node(value) }; if value < root.value { root.left = insert(root.left, value) } else { root.right = insert(root.right, value) }; return root }
var root: Node? = nil
for value in [4, 2, 6, 1, 3, 5, 7] { root = insert(root, value) }
print(render(root))
Complexity
- Time: O(h) per insert
- Space: O(n)
Implementation notes
final class Nodegives each tree node reference semantics;valueis alet Int, whileleftandrightare mutableNode?child references.init(_ value: Int, _ left: Node? = nil, _ right: Node? = nil)defaults new child links tonil.insert(_ root: Node?, _ value: Int) -> Nodehandles an empty subtree withguard let root = root else { return Node(value) }.- Recursive insertion mutates child references in place:
root.left = insert(root.left, value)forvalue < root.value, otherwiseroot.right = insert(root.right, value). - Equal values would follow the
elsebranch to the right; the checked input has no duplicates. var root: Node? = nilis reassigned after each insertion so the first returned node becomes the tree root.- The trace records insertion paths for
4, 2, 6, 1, 3, 5, 7, ending at4(2(1,3),6(5,7)); the adversarial contrast shows sorted inserts[1, 2, 3, 4]forming1(_,2(_,3(_,4)))with height4. render(_:)prints_fornilchildren and nested node text, soprint(render(root))outputs4(2(1,3),6(5,7)).