Sorting
Bubble Sort
Repeatedly walk the array comparing adjacent pairs and swapping any that are
out of order. After pass k, the k largest elements are in their final
positions at the end. Stop early when a full pass makes zero swaps.
Algorithm
Canonical input [5, 1, 4, 2, 8] finishes after three passes: two with
swaps, then a clean pass that triggers the early exit. Final array
[1, 2, 4, 5, 8].
adjacent-pair compare and swap
Inner loop walks `j` from `0` to `n - i - 2` comparing `arr[j]` and `arr[j + 1]`.
early exit
A `swapped` flag set false at the start of each pass. If no swap happened, break out of the outer loop.
Basic Implementation
basic.swift
Replay: real traced execution (multi-file project)
var arr = [5, 1, 4, 2, 8]
let n = arr.count
for i in 0..<(n - 1) {
var swapped = false
for j in 0..<(n - i - 1) {
if arr[j] > arr[j + 1] {
let tmp = arr[j]
arr[j] = arr[j + 1]
arr[j + 1] = tmp
swapped = true
}
}
if !swapped {
break
}
}
print(arr)
arr ← [5, 1, 4, 2, 8]
1var arr = [5, 1, 4, 2, 8]2let n = arr.countvalues this step[5, 1, 4, 2, 8]arrn ← 5
1var arr = [5, 1, 4, 2, 8]2let n = arr.count3for i in 0..<(n - 1) {values this step5n[5, 1, 4, 2, 8]arrswapped ← false
3for i in 0..<(n - 1) {4 var swapped = false5 for j in 0..<(n - i - 1) {values this stepfalseswappedarr[j] > arr[j+1] ← true
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this steptruearr[j] > arr[j+1][5, 1, 4, 2, 8]arr0j5arr[j]1arr[j+1]arr ← [1, 5, 4, 2, 8], swapped ← true
7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmpvalues this step[5, 1, 4, 2, 8] → [1, 5, 4, 2, 8]arrtrueswappedarr[j] > arr[j+1] ← true
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this steptruearr[j] > arr[j+1][1, 5, 4, 2, 8]arr1j5arr[j]4arr[j+1]arr ← [1, 4, 5, 2, 8], swapped ← true
7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmpvalues this step[1, 5, 4, 2, 8] → [1, 4, 5, 2, 8]arrtrueswappedarr[j] > arr[j+1] ← true
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this steptruearr[j] > arr[j+1][1, 4, 5, 2, 8]arr2j5arr[j]2arr[j+1]arr ← [1, 4, 2, 5, 8], swapped ← true
7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmpvalues this step[1, 4, 5, 2, 8] → [1, 4, 2, 5, 8]arrtrueswappedarr[j] > arr[j+1] ← false
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this stepfalsearr[j] > arr[j+1][1, 4, 2, 5, 8]arr3j5arr[j]8arr[j+1]swapped ← false
3for i in 0..<(n - 1) {4 var swapped = false5 for j in 0..<(n - i - 1) {values this stepfalseswappedarr[j] > arr[j+1] ← false
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this stepfalsearr[j] > arr[j+1][1, 4, 2, 5, 8]arr0j1arr[j]4arr[j+1]arr[j] > arr[j+1] ← true
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this steptruearr[j] > arr[j+1][1, 4, 2, 5, 8]arr1j4arr[j]2arr[j+1]arr ← [1, 2, 4, 5, 8], swapped ← true
7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmpvalues this step[1, 4, 2, 5, 8] → [1, 2, 4, 5, 8]arrtrueswappedarr[j] > arr[j+1] ← false
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr2j4arr[j]5arr[j+1]swapped ← false
3for i in 0..<(n - 1) {4 var swapped = false5 for j in 0..<(n - i - 1) {values this stepfalseswappedarr[j] > arr[j+1] ← false
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr0j1arr[j]2arr[j+1]arr[j] > arr[j+1] ← false
5for j in 0..<(n - i - 1) {6 if arr[j] > arr[j + 1] {7 let tmp = arr[j]values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr1j2arr[j]4arr[j+1]loop ← break
13if !swapped {14 break15}values this stepbreakloopfalseswappedstdout ← [1, 2, 4, 5, 8]
16}17print(arr)values this step[1, 2, 4, 5, 8]stdout[1, 2, 4, 5, 8]arr
Complexity
- Time: O(n^2) worst and average; O(n) best (already sorted with early exit)
- Space: O(1)
- Stable: yes
Implementation notes
- Swift: nested
forloops with the early-exitswappedflag.arr.sort()would hide the comparison-and-swap the lesson is teaching. - The explicit
let tmp = arr[j]; arr[j] = arr[j+1]; arr[j+1] = tmpthree-line swap keeps the move visible without leaning on thearr.swapAt(j, j+1)helper. - The replay distinguishes compare frames from swap frames so the
moving pivot value is visible. The pass number and
swappedflag appear in the trace.