Repeatedly walk the array comparing adjacent pairs and swapping any that are out of order. After pass k, the k largest elements are in their final positions at the end. Stop early when a full pass makes zero swaps.

Algorithm

Canonical input [5, 1, 4, 2, 8] finishes after three passes: two with swaps, then a clean pass that triggers the early exit. Final array [1, 2, 4, 5, 8].

adjacent-pair compare and swap Inner loop walks `j` from `0` to `n - i - 2` comparing `arr[j]` and `arr[j + 1]`.
early exit A `swapped` flag set false at the start of each pass. If no swap happened, break out of the outer loop.

Basic Implementation

basic.swift
Replay: real traced execution (multi-file project)
var arr = [5, 1, 4, 2, 8]
let n = arr.count
for i in 0..<(n - 1) {
	var swapped = false
	for j in 0..<(n - i - 1) {
		if arr[j] > arr[j + 1] {
			let tmp = arr[j]
			arr[j] = arr[j + 1]
			arr[j + 1] = tmp
			swapped = true
		}
	}
	if !swapped {
		break
	}
}
print(arr)
  1. arr ← [5, 1, 4, 2, 8]

    1var arr = [5, 1, 4, 2, 8]2let n = arr.count
    values this step[5, 1, 4, 2, 8]arr
  2. n ← 5

    1var arr = [5, 1, 4, 2, 8]2let n = arr.count3for i in 0..<(n - 1) {
    values this step5n[5, 1, 4, 2, 8]arr
  3. swapped ← false

    3for i in 0..<(n - 1) {4	var swapped = false5	for j in 0..<(n - i - 1) {
    values this stepfalseswapped
  4. arr[j] > arr[j+1] ← true

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this steptruearr[j] > arr[j+1][5, 1, 4, 2, 8]arr0j5arr[j]1arr[j+1]
  5. arr ← [1, 5, 4, 2, 8], swapped ← true

    7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmp
    values this step[5, 1, 4, 2, 8] [1, 5, 4, 2, 8]arrtrueswapped
  6. arr[j] > arr[j+1] ← true

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this steptruearr[j] > arr[j+1][1, 5, 4, 2, 8]arr1j5arr[j]4arr[j+1]
  7. arr ← [1, 4, 5, 2, 8], swapped ← true

    7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmp
    values this step[1, 5, 4, 2, 8] [1, 4, 5, 2, 8]arrtrueswapped
  8. arr[j] > arr[j+1] ← true

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this steptruearr[j] > arr[j+1][1, 4, 5, 2, 8]arr2j5arr[j]2arr[j+1]
  9. arr ← [1, 4, 2, 5, 8], swapped ← true

    7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmp
    values this step[1, 4, 5, 2, 8] [1, 4, 2, 5, 8]arrtrueswapped
  10. arr[j] > arr[j+1] ← false

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this stepfalsearr[j] > arr[j+1][1, 4, 2, 5, 8]arr3j5arr[j]8arr[j+1]
  11. swapped ← false

    3for i in 0..<(n - 1) {4	var swapped = false5	for j in 0..<(n - i - 1) {
    values this stepfalseswapped
  12. arr[j] > arr[j+1] ← false

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this stepfalsearr[j] > arr[j+1][1, 4, 2, 5, 8]arr0j1arr[j]4arr[j+1]
  13. arr[j] > arr[j+1] ← true

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this steptruearr[j] > arr[j+1][1, 4, 2, 5, 8]arr1j4arr[j]2arr[j+1]
  14. arr ← [1, 2, 4, 5, 8], swapped ← true

    7let tmp = arr[j]8arr[j] = arr[j + 1]9arr[j + 1] = tmp
    values this step[1, 4, 2, 5, 8] [1, 2, 4, 5, 8]arrtrueswapped
  15. arr[j] > arr[j+1] ← false

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr2j4arr[j]5arr[j+1]
  16. swapped ← false

    3for i in 0..<(n - 1) {4	var swapped = false5	for j in 0..<(n - i - 1) {
    values this stepfalseswapped
  17. arr[j] > arr[j+1] ← false

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr0j1arr[j]2arr[j+1]
  18. arr[j] > arr[j+1] ← false

    5for j in 0..<(n - i - 1) {6	if arr[j] > arr[j + 1] {7		let tmp = arr[j]
    values this stepfalsearr[j] > arr[j+1][1, 2, 4, 5, 8]arr1j2arr[j]4arr[j+1]
  19. loop ← break

    13if !swapped {14	break15}
    values this stepbreakloopfalseswapped
  20. stdout ← [1, 2, 4, 5, 8]

    16}17print(arr)
    values this step[1, 2, 4, 5, 8]stdout[1, 2, 4, 5, 8]arr

Complexity

  • Time: O(n^2) worst and average; O(n) best (already sorted with early exit)
  • Space: O(1)
  • Stable: yes

Implementation notes

  • Swift: nested for loops with the early-exit swapped flag. arr.sort() would hide the comparison-and-swap the lesson is teaching.
  • The explicit let tmp = arr[j]; arr[j] = arr[j+1]; arr[j+1] = tmp three-line swap keeps the move visible without leaning on the arr.swapAt(j, j+1) helper.
  • The replay distinguishes compare frames from swap frames so the moving pivot value is visible. The pass number and swapped flag appear in the trace.