Curvature pressure is scanned across inverse radius and direct factor. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Curvature pressure has a radius input and a surface-count factor

The radius marker is visible in the diagram. The factor is a checked integer that distinguishes a droplet-style surface from a two-sided film surface.

ΔP=kγR=26 N/m/3 m=4 Pa\Delta P=k{\gamma\over R}=2\cdot6\ \text{N/m}/3\ \text{m}=4\ \text{Pa}
Curvature radius contrastLarger radius lowers the checked pressure jump.radiuspressureradiuspressurebase radiuslarger radius

Increasing radius lowers the pressure jump

Gamma and factor are fixed here. The three radius rows expose the inverse relationship without decimal approximations.

kγRΔP26 N/m2 m6 Pa26 N/m3 m4 Pa26 N/m6 m2 Pa\begin{array}{c|c|c|c}k&\gamma&R&\Delta P\\2&6\ \text{N/m}&2\ \text{m}&6\ \text{Pa}\\2&6\ \text{N/m}&3\ \text{m}&4\ \text{Pa}\\2&6\ \text{N/m}&6\ \text{m}&2\ \text{Pa}\\\end{array}

Increasing the curvature factor raises the pressure jump

The factor rows keep radius fixed. A two-sided film factor gives a larger pressure jump than a one-sided training case.

kγRΔP16 N/m3 m2 Pa26 N/m3 m4 Pa46 N/m3 m8 Pa\begin{array}{c|c|c|c}k&\gamma&R&\Delta P\\1&6\ \text{N/m}&3\ \text{m}&2\ \text{Pa}\\2&6\ \text{N/m}&3\ \text{m}&4\ \text{Pa}\\4&6\ \text{N/m}&3\ \text{m}&8\ \text{Pa}\\\end{array}
Curvature factor contrastSame radius, larger factor, larger pressure jump.radiuspressureradiuspressurebase factorlarger factor