Capacitor energy is computed from charge and capacitance. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Charge and capacitance set capacitor energy

The standalone source uses charge 2 coulombs and capacitance 4 farads, giving capacitor energy 1/2 joule.

EC=Q22C=2224=12 JE_C=\frac{Q^{2}}{2C}=\frac{2^{2}}{2\cdot 4}=\tfrac{1}{2}\ \text{J}
Capacitor energy sourceThe half factor and charge square are checked.snapshot0Charge=2 Csnapshot0Capacitance=4 Fsnapshot0Flux=0 Wbsnapshot0Inductance=1 Hsnapshot0CapacitorEnergy=1/2 Jsnapshot0InductorEnergy=0 Jsnapshot0TotalEnergy=1/2 J

The capacitor term is one store of the mode

The checked standalone total is 1/2 joule because this source sets the flux term to 0.

Etotal=12 JE_{\text{total}}=\tfrac{1}{2}\ \text{J}
Energy storesEach store contributes to the same total.snapshot0Charge=2 Csnapshot0Capacitance=4 Fsnapshot0Flux=0 Wbsnapshot0Inductance=1 Hsnapshot0CapacitorEnergy=1/2 Jsnapshot0InductorEnergy=0 Jsnapshot0TotalEnergy=1/2 J