Find the first copy of a duplicated target by recording matches and continuing to search the left half.

Algorithm

Basic Implementation

basic.sql
.mode list
.headers off
CREATE TABLE arr(idx INTEGER PRIMARY KEY, val INTEGER);
INSERT INTO arr(idx, val) VALUES
  (0, 1), (1, 2), (2, 4), (3, 4), (4, 4), (5, 7), (6, 9);
WITH RECURSIVE search(step, lo, hi, result) AS (
  SELECT 0, 0, 6, -1
  UNION ALL
  SELECT
    step + 1,
    CASE WHEN (SELECT val FROM arr WHERE idx = lo + (hi - lo) / 2) < 4
         THEN lo + (hi - lo) / 2 + 1 ELSE lo END,
    CASE WHEN (SELECT val FROM arr WHERE idx = lo + (hi - lo) / 2) >= 4
         THEN lo + (hi - lo) / 2 - 1 ELSE hi END,
    CASE WHEN (SELECT val FROM arr WHERE idx = lo + (hi - lo) / 2) = 4
         THEN lo + (hi - lo) / 2 ELSE result END
  FROM search
  WHERE lo <= hi
)
SELECT result FROM search ORDER BY step DESC LIMIT 1;

Complexity

  • Time: O(log n)
  • Space: O(1)

Implementation notes

  • Keep the explicit control flow. Library shortcuts would hide the state changes this lesson is meant to replay.
  • The final output is intentionally small and deterministic for cross-language comparison.
execution replay The checked-in replay follows the language-neutral state table for `search-binary-first`.
cross-language comparison This SQL DSA version keeps the same data and final output as every other DSA book in this wave.