Changing only the collector resistance moves load demand against the same drive limit.

Changing only the collector resistance moves load demand against the same drive limit. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Six ohms asks for only two amperes

With collector resistor 6 ohm, load demand is 2 A. Drive stays 3 A, so collector current is 2 A and output is 0 V.

Iload=2 A,3 A>2 AI_\text{load}=2\ \text{A},\quad 3\ \text{A}>2\ \text{A}
Collector load-resistance scanLoad demand and actual collector current are checked.output 0 Vdrive 3 Aload 2 Acollector 2 Asaturation

Four ohms is exactly the saturation boundary

With collector resistor 4 ohm, load demand is 3 A. Drive stays 3 A, so collector current is 3 A and output is 0 V.

Iload=3 A,3 A=3 AI_\text{load}=3\ \text{A},\quad 3\ \text{A}=3\ \text{A}
Collector load-resistance scanLoad demand and actual collector current are checked.output 0 Vdrive 3 Aload 3 Acollector 3 Asaturation

Three ohms asks for more current than beta can supply

With collector resistor 3 ohm, load demand is 4 A. Drive stays 3 A, so collector current is 3 A and output is 3 V.

Iload=4 A,3 A<4 AI_\text{load}=4\ \text{A},\quad 3\ \text{A}<4\ \text{A}
Collector load-resistance scanLoad demand and actual collector current are checked.drive 3 Aload 4 Acollector 3 Aoutput 3 Vactive