Build a Binary Tree

Create a fixed seven-node binary tree and render its shape.

Algorithm

The canonical tree is 4(2(1,3),6(5,7)), so this Scala DSA implementation can be compared directly with the rest of the DSA track.

Basic Implementation

basic.scala

import scala.collection.mutable.{ArrayBuffer, Queue}
class Node(val value: Int, var left: Node = null, var right: Node = null)
object Main {
  def render(node: Node): String = {
    if (node == null) "_"
    else if (node.left == null && node.right == null) node.value.toString
    else s"${node.value}(${render(node.left)},${render(node.right)})"
  }
  def sampleTree(): Node = new Node(4, new Node(2, new Node(1), new Node(3)), new Node(6, new Node(5), new Node(7)))
  def listString(values: Seq[Int]): String = values.mkString("[", ", ", "]")
  def main(args: Array[String]): Unit = { println(render(sampleTree())) }
}

Complexity

Time: O(n)
Space: O(n)

Implementation notes

Render tree structure explicitly instead of printing node objects.
The replay highlights the node, traversal state, queue, path, or search cursor that changes at each step.

node links A node stores one value plus references to its left and right children.