Searching
Binary Search (Recursive)
Use the same binary-search window as the iterative lesson, but pass lo and hi through recursive calls.
Algorithm
execution replay
The checked-in replay follows the language-neutral state table for `search-binary-recursive`.
cross-language comparison
This Scala DSA version keeps the same data and final output as every other DSA book in this wave.
Basic Implementation
basic.scala
Replay: real traced execution (multi-file project)
object Main {
def search(arr: Array[Int], target: Int, lo: Int, hi: Int): Int = {
if (lo > hi) return -1
val mid = lo + (hi - lo) / 2
if (arr(mid) == target) return mid
if (arr(mid) < target) return search(arr, target, mid + 1, hi)
search(arr, target, lo, mid - 1)
}
def main(args: Array[String]): Unit = {
val arr = Array(1, 3, 5, 7, 9, 11, 13)
val target = 11
println(search(arr, target, 0, arr.length - 1))
}
}
lo ← 0, hi ← 6, target ← 11
1object Main {2 def search(arr: Array[Int], target: Int, lo: Int, hi: Int): Int = {values this step0lo6hi11targetmid ← 3, arr[mid] ← 7, next call ← (4, 6)
3if (lo > hi) return -14val mid = lo + (hi - lo) / 25if (arr(mid) == target) return midvalues this step3mid7arr[mid](4, 6)next call0lo6himid ← 5, arr[mid] ← 11, result ← 5
3if (lo > hi) return -14val mid = lo + (hi - lo) / 25if (arr(mid) == target) return midvalues this step5mid11arr[mid]5result4lo6histdout ← 5
12 val target = 1113 println(search(arr, target, 0, arr.length - 1))14}values this step5stdout5result
Complexity
- Time: O(log n)
- Space: O(log n) call stack
Implementation notes
search(arr: Array[Int], target: Int, lo: Int, hi: Int): Inttakes the ScalaArray[Int], target, and current bounds as parameters on each call.- The miss base case is
if (lo > hi) return -1, so-1is the not-found sentinel. val mid = lo + (hi - lo) / 2computes the current index withIntinteger division before readingarr(mid).- A match returns
midimmediately. Ifarr(mid) < target, the function recurses withmid + 1, hi; otherwise it recurses withlo, mid - 1. - The top-level input is
val arr = Array(1, 3, 5, 7, 9, 11, 13)andval target = 11. - The trace starts with
search(lo=0, hi=6), computesmid = 3, seesarr(mid) = 7, and recurses right to(4, 6). - The next call computes
mid = 5, seesarr(mid) = 11, returns5, andprintln(search(...))prints the exact output5.