Recursion and Dynamic Programming
Fibonacci with Memoization
Compute fib(n) recursively. Cache each fib(k) in a memo map so each
subproblem is solved at most once.
Algorithm
Canonical input n = 6 produces fib(6) = 8. Replay highlights every
memo write and every cache hit.
memoization
A `HashMap<i32, i32>` keyed by `n` stores each completed subproblem. Before recursing, check `memo.get(&n)`: a hit returns immediately, a miss descends.
explicit memo state
The memo is threaded through the recursion as `&mut HashMap<i32, i32>` so the lesson stays about caching, not global state.
Basic Implementation
basic.rs
Replay: real traced execution (multi-file project)
use std::collections::HashMap;
fn fib(n: i32, memo: &mut HashMap<i32, i32>) -> i32 {
if let Some(&v) = memo.get(&n) {
return v;
}
if n < 2 {
memo.insert(n, n);
return n;
}
let value = fib(n - 1, memo) + fib(n - 2, memo);
memo.insert(n, value);
value
}
fn main() {
let mut memo: HashMap<i32, i32> = HashMap::new();
let result = fib(6, &mut memo);
println!("{}", result);
}
memo ← {}, action ← miss -> descend fib(5)
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{}memomiss -> descend fib(5)action6nmemo ← {}, action ← miss -> descend fib(4)
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{}memomiss -> descend fib(4)action5nmemo ← {}, action ← miss -> descend fib(3)
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{}memomiss -> descend fib(3)action4nmemo ← {}, action ← miss -> descend fib(2)
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{}memomiss -> descend fib(2)action3nmemo ← {}, action ← miss -> descend fib(1)
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{}memomiss -> descend fib(1)action2nmemo ← {1: 1}, action ← base 1; memo[1] = 1; return
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{1: 1}memobase 1; memo[1] = 1; returnaction1nmemo ← {0: 0, 1: 1}, action ← base 0; memo[0] = 0; fib(2)=1; memo[2] = 1
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{0: 0, 1: 1}memobase 0; memo[0] = 0; fib(2)=1; memo[2] = 1action0nmemo ← {0: 0, 1: 1, 2: 1, 3: 2}, action ← hit 1; fib(3)=2; memo[3] = 2
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{0: 0, 1: 1, 2: 1, 3: 2}memohit 1; fib(3)=2; memo[3] = 2action1nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3}, action ← hit 1; fib(4)=3; memo[4] = 3
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3}memohit 1; fib(4)=3; memo[4] = 3action2nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5}, action ← hit 2; fib(5)=5; memo[5] = 5
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5}memohit 2; fib(5)=5; memo[5] = 5action3nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5, 6: 8}, action ← hit 3; fib(6)=8; memo[6] = 8
10}11let value = fib(n - 1, memo) + fib(n - 2, memo);12memo.insert(n, value);values this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5, 6: 8}memohit 3; fib(6)=8; memo[6] = 8action4nstdout ← 8
18 let result = fib(6, &mut memo);19 println!("{}", result);20}values this step8stdout8result
Complexity
- Time: O(n) with memoization (vs. O(2^n) without)
- Space: O(n) memo + O(n) call stack
Implementation notes
- Rust: the recursion takes the memo as
&mut HashMap<i32, i32>rather than a global, which keeps Rust's ownership model honest without hiding the lesson behindthread_local!or aMutex. Theif let Some(&v) = memo.get(&n)pattern is the canonical "did I see this key" test. - The replay shows the call stack on one side and the memo map on the other so memo writes and cache hits are visually distinct.