Sorting
Bubble Sort
Repeatedly walk the array comparing adjacent pairs and swapping any that are
out of order. After pass k, the k largest elements are in their final
positions at the end. Stop early when a full pass makes zero swaps.
Algorithm
Canonical input [5, 1, 4, 2, 8] finishes after three passes: two with
swaps, then a clean pass that triggers the early exit. Final array
[1, 2, 4, 5, 8].
Basic Implementation
basic.rb
arr = [5, 1, 4, 2, 8]
n = arr.length
i = 0
done = false
while i < n - 1 && !done
swapped = false
j = 0
while j < n - i - 1
if arr[j] > arr[j + 1]
tmp = arr[j]
arr[j] = arr[j + 1]
arr[j + 1] = tmp
swapped = true
end
j = j + 1
end
if !swapped
done = true
end
i = i + 1
end
puts arr.inspect
Complexity
- Time: O(n^2) worst and average; O(n) best (already sorted with early exit)
- Space: O(1)
- Stable: yes
Implementation notes
- Ruby: explicit
whileloops with locali,j,done, andswappedso the early-exit flow stays visible. The stdlibarr.sort(orarr.sort!) would hide the comparison-and-swap the lesson is teaching, andbreakinside a block would obscure thedoneflag. - The explicit
tmp = arr[j]; arr[j] = arr[j+1]; arr[j+1] = tmpthree-line swap keeps the move visible without leaning on parallel assignment likearr[j], arr[j+1] = arr[j+1], arr[j]. - The replay distinguishes compare frames from swap frames so the
moving pivot value is visible. The pass number and
swappedflag appear in the trace.
adjacent-pair compare and swap
Inner loop walks `j` from `0` to `n - i - 2` comparing `arr[j]` and `arr[j + 1]`.
early exit
A `swapped` flag set false at the start of each pass. If no swap happened, flip a `done` flag and break out of the outer loop.