Searching
Binary Search First Occurrence
Find the first copy of a duplicated target by recording matches and continuing to search the left half.
Algorithm
execution replay
The checked-in replay follows the language-neutral state table for `search-binary-first`.
cross-language comparison
This Ruby DSA version keeps the same data and final output as every other DSA book in this wave.
Basic Implementation
basic.rb
Replay: real traced execution (multi-file project)
arr = [1, 2, 4, 4, 4, 7, 9]
target = 4
lo = 0
hi = arr.length - 1
result = -1
while lo <= hi
mid = lo + (hi - lo) / 2
if arr[mid] == target
result = mid
hi = mid - 1
elsif arr[mid] < target
lo = mid + 1
else
hi = mid - 1
end
end
puts result
arr ← [1, 2, 4, 4, 4, 7, 9], target ← 4, result ← -1
1arr = [1, 2, 4, 4, 4, 7, 9]2target = 4values this step[1, 2, 4, 4, 4, 7, 9]arr4target-1resulthi ← 2, mid ← 3, result ← 3
6while lo <= hi7 mid = lo + (hi - lo) / 28 if arr[mid] == targetvalues this step6 → 2hi3mid3result0lolo ← 2, mid ← 1
6while lo <= hi7 mid = lo + (hi - lo) / 28 if arr[mid] == targetvalues this step0 → 2lo1mid2hi3resulthi ← 1, result ← 2, mid ← 2
6while lo <= hi7 mid = lo + (hi - lo) / 28 if arr[mid] == targetvalues this step2 → 1hi3 → 2result2mid2lostdout ← 2
1arr = [1, 2, 4, 4, 4, 7, 9]2target = 4values this step2stdout2result
Complexity
- Time: O(log n)
- Space: O(1)
Implementation notes
arris a RubyArrayread by index; the search never mutates it.lo,hi,mid, andresultare local integer variables reassigned during thewhile lo <= hiloop.- The midpoint uses
mid = lo + (hi - lo) / 2; Ruby integer division keepsmidas an integer index. resultstarts at-1, so a miss would keep the sentinel value.- On
arr[mid] == target, the code recordsresult = midand then setshi = mid - 1to keep searching for an earlier copy. - If
arr[mid] < target,lo = mid + 1; otherwisehi = mid - 1. - The trace first matches at index
3, moves left, skips value2at index1, then matches index2as the first occurrence. puts resultprints the final scalar index2.