Find the first copy of a duplicated target by recording matches and continuing to search the left half.

Algorithm

Basic Implementation

basic.rb
arr = [1, 2, 4, 4, 4, 7, 9]
target = 4
lo = 0
hi = arr.length - 1
result = -1
while lo <= hi
	mid = lo + (hi - lo) / 2
	if arr[mid] == target
		result = mid
		hi = mid - 1
	elsif arr[mid] < target
		lo = mid + 1
	else
		hi = mid - 1
	end
end
puts result

Complexity

  • Time: O(log n)
  • Space: O(1)

Implementation notes

  • Keep the explicit control flow. Library shortcuts would hide the state changes this lesson is meant to replay.
  • The final output is intentionally small and deterministic for cross-language comparison.
execution replay The checked-in replay follows the language-neutral state table for `search-binary-first`.
cross-language comparison This Ruby DSA version keeps the same data and final output as every other DSA book in this wave.