Bell-pair preparation is built in two visible moves: split the control into two equal branches, then let CNOT copy only the branch where the control is 1. The final ledger has two matching branches, 00 and 11, each with probability one half, rather than four equally likely rows. This is an ideal circuit-state check; real preparation needs calibrated pulses, coherence time, readout efficiency, repeated shots, and uncertainty.

A simple two-gate sequence prepares a two-qubit state with exactly two correlated branches. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Put the control qubit in two branches

Start with the control qubit in zero. An H gate makes two equal control branches with amplitude one over square root of 2.

H∣0⟩=12∣0⟩+12∣1⟩H\lvert 0\rangle = \frac{1}{\sqrt{2}}\lvert 0\rangle + \frac{1}{\sqrt{2}}\lvert 1\rangle
Control superpositionThe first qubit is prepared as two equal branches.state1 zero0 onestate1/sqrt(2) zero1/sqrt(2) oneHgate

Attach a target initialized to zero

Before CNOT, the two-qubit state has the same two control branches and a target zero in each branch.

12∣0,0⟩+12∣1,0⟩\frac{1}{\sqrt{2}}\lvert 0,0\rangle + \frac{1}{\sqrt{2}}\lvert 1,0\rangle
CNOT inputThe CNOT input has support only on zero-zero and one-zero.state1/sqrt(2) zerozero0 zeroone1/sqrt(2) onezero0 oneonestate1/sqrt(2) zerozero0 zeroone0 onezero1/sqrt(2) oneoneCNOTgate

CNOT flips only the target branch with control one

CNOT leaves zero-zero unchanged and maps one-zero to one-one. The two surviving branches now carry matching bit values.

inputoutput∣0,0⟩∣0,0⟩∣1,0⟩∣1,1⟩\begin{array}{c|c}\text{input}&\text{output}\\\lvert 0,0\rangle&\lvert 0,0\rangle\\\lvert 1,0\rangle&\lvert 1,1\rangle\end{array}
CNOT outputThe output support is zero-zero and one-one.state1/sqrt(2) zerozero0 zeroone1/sqrt(2) onezero0 oneonestate1/sqrt(2) zerozero0 zeroone0 onezero1/sqrt(2) oneoneCNOTgate

The output is a correlated two-qubit state

The state is not four equally likely rows. It has exactly two branches, each with probability one half.

outcomeP∣0,0⟩12∣0,1⟩0∣1,0⟩0∣1,1⟩12\begin{array}{c|c}\text{outcome}&P\\\lvert 0,0\rangle&\frac{1}{2}\\\lvert 0,1\rangle&0\\\lvert 1,0\rangle&0\\\lvert 1,1\rangle&\frac{1}{2}\end{array}
Prepared Bell pairThe gate output and the probability table agree.state1/sqrt(2) zerozero0 zeroone1/sqrt(2) onezero0 oneonestate1/sqrt(2) zerozero0 zeroone0 onezero1/sqrt(2) oneoneCNOTgate