Phase loss changes visible signal by a coherent fraction, not by relabeling shots. Exact arithmetic here means exact results for the stated model inputs; measured inputs still carry uncertainty and significant-figure limits.

highlighted = computed this step

Four fifths coherence keeps forty visible counts

With 64 coherent shots out of 80, the coherent fraction is 4/5. The ideal visible count 50 scales to 40.

5045=4050\cdot\frac{4}{5}=40
Phase-retention scan rowVisible counts follow the coherent fraction.4/5coherent1/5dephasedphase loss

Three fifths coherence gives the capstone signal

The capstone row has 48 coherent and 32 dephased shots. That ratio turns 50 ideal visible counts into 30.

5035=3050\cdot\frac{3}{5}=30
Phase-retention scan rowThe middle row matches the open-system audit.3/5coherent2/5dephasedphase loss

Two fifths coherence leaves twenty visible counts

If coherent shots fall to 32 out of 80, the same ideal signal produces only 20 visible counts.

5025=2050\cdot\frac{2}{5}=20
Phase-retention scan rowThree rows separate phase loss from population loss.2/5coherent3/5dephasedphase loss