Linked Structures
Delete by Value
Find the node before the target value and rewire its next pointer so the target node leaves the chain.
Algorithm
The replay labels nodes by value, such as node(20), and never exposes object
identity or memory addresses. This Python DSA implementation uses the
same small chain as the rest of the DSA track.
predecessor
Deletion needs the node before the one being removed.
rewiring
The predecessor skips the target and points at the target's next node.
Basic Implementation
basic.py
Replay: real traced execution (multi-file project)
class Node:
__slots__ = ("value", "next")
def __init__(self, value, nxt=None):
self.value = value
self.next = nxt
def render(head):
parts = []
cursor = head
while cursor is not None:
parts.append(str(cursor.value))
cursor = cursor.next
return " -> ".join(parts) + " -> null"
head = Node(10, Node(20, Node(30, Node(40))))
target = 30
cursor = head
while cursor.next is not None:
if cursor.next.value == target:
cursor.next = cursor.next.next
break
cursor = cursor.next
print(render(head))
head ← 10 -> 20 -> 30 -> 40 -> null, target ← 30
1class Node:2 __slots__ = ("value", "next")values this step10 -> 20 -> 30 -> 40 -> nullhead30targetcursor ← node(20)
9cursor = head10while cursor is not None:11 parts.append(str(cursor.value))values this stepnode(10) → node(20)cursorcursor.next ← node(40)
19if cursor.next.value == target:20 cursor.next = cursor.next.next21 breakvalues this stepnode(30) → node(40)cursor.nextstdout ← 10 -> 20 -> 40 -> null
22 cursor = cursor.next23print(render(head))values this step10 -> 20 -> 40 -> nullstdout10 -> 20 -> 40 -> nullhead
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Keep the explicit node and pointer/reference operations; array shortcuts hide the linked-list state this lesson is meant to replay.
- The final output prints the chain in a deterministic
a -> b -> nullform for cross-language comparison.