Represent sequential outcomes as nested branches and multiply branch probabilities to get leaf outcome probabilities.

Leaf probabilities can be summed to verify they total 1.

Example

Use a path table to multiply branch probabilities and add outcomes.

highlighted = computed this step

Step 1 — Branch probabilities

List the branch probability for each split.

branches=2p=12branches= \hl{2} \quad p= \hlmath{\frac{1}{2}}

Step 2 — Path HH

Multiply branch probabilities for path HH.

pathfirstpasecondpbprodHHH12H1214HTTHTT\begin{array}{cccccc}\text{path} & \text{first} & \text{pa} & \text{second} & \text{pb} & \text{prod} \\ \text{HH} & \text{H} & \hlmath{\frac{1}{2}} & \text{H} & \hlmath{\frac{1}{2}} & \hlmath{\frac{1}{4}} \\ \text{HT} & \square & \square & \square & \square & \square \\ \text{TH} & \square & \square & \square & \square & \square \\ \text{TT} & \square & \square & \square & \square & \square\end{array}

Step 3 — Path HT

Multiply branch probabilities for path HT.

pathfirstpasecondpbprodHHH12H1214HTH12T1214THTT\begin{array}{cccccc}\text{path} & \text{first} & \text{pa} & \text{second} & \text{pb} & \text{prod} \\ \text{HH} & \text{H} & \frac{1}{2} & \text{H} & \frac{1}{2} & \frac{1}{4} \\ \text{HT} & \text{H} & \hlmath{\frac{1}{2}} & \text{T} & \hlmath{\frac{1}{2}} & \hlmath{\frac{1}{4}} \\ \text{TH} & \square & \square & \square & \square & \square \\ \text{TT} & \square & \square & \square & \square & \square\end{array}

Step 4 — Path TH

Multiply branch probabilities for path TH.

pathfirstpasecondpbprodHHH12H1214HTH12T1214THT12H1214TT\begin{array}{cccccc}\text{path} & \text{first} & \text{pa} & \text{second} & \text{pb} & \text{prod} \\ \text{HH} & \text{H} & \frac{1}{2} & \text{H} & \frac{1}{2} & \frac{1}{4} \\ \text{HT} & \text{H} & \frac{1}{2} & \text{T} & \frac{1}{2} & \frac{1}{4} \\ \text{TH} & \text{T} & \hlmath{\frac{1}{2}} & \text{H} & \hlmath{\frac{1}{2}} & \hlmath{\frac{1}{4}} \\ \text{TT} & \square & \square & \square & \square & \square\end{array}

Step 5 — Path TT

Multiply branch probabilities for path TT.

pathfirstpasecondpbprodHHH12H1214HTH12T1214THT12H1214TTT12T1214\begin{array}{cccccc}\text{path} & \text{first} & \text{pa} & \text{second} & \text{pb} & \text{prod} \\ \text{HH} & \text{H} & \frac{1}{2} & \text{H} & \frac{1}{2} & \frac{1}{4} \\ \text{HT} & \text{H} & \frac{1}{2} & \text{T} & \frac{1}{2} & \frac{1}{4} \\ \text{TH} & \text{T} & \frac{1}{2} & \text{H} & \frac{1}{2} & \frac{1}{4} \\ \text{TT} & \text{T} & \hlmath{\frac{1}{2}} & \text{T} & \hlmath{\frac{1}{2}} & \hlmath{\frac{1}{4}}\end{array}

Step 6 — Sum paths

Add all path probabilities.

14+14+14+14=1\frac{1}{4} + \frac{1}{4} + \frac{1}{4} + \frac{1}{4} = \hl{1}
tree-diagram Product of branch probabilities gives leaf probabilities.