Hash Tables
First Non-Repeating Value
Find the first input value whose final frequency is one.
Algorithm
Canonical input [3, 5, 2, 5, 3, 8, 2] prints 8.
The replay uses the same input in every language, so this PHP DSA
implementation can be compared directly with the rest of the DSA track.
Basic Implementation
basic.php
<?php
$arr = [3, 5, 2, 5, 3, 8, 2];
$count = [];
foreach ($arr as $value) {
$count[$value] = ($count[$value] ?? 0) + 1;
}
foreach ($arr as $value) {
if ($count[$value] === 1) {
echo $value . PHP_EOL;
break;
}
}
?>
Complexity
- Time: O(n) average
- Space: O(k) for k distinct values
Implementation notes
- The checked PHP source uses the numeric input array
$arr = [3, 5, 2, 5, 3, 8, 2], not a string scan. $count = []is a PHP associative array used as the frequency table.- The first
foreach ($arr as $value)walks values in input order and updates counts with$count[$value] = ($count[$value] ?? 0) + 1. - The null-coalescing read treats a missing key as
0before the increment. - The trace grows the table as
{3: 1},{3: 1, 5: 1},{3: 1, 5: 1, 2: 1}, then finishes at{3: 2, 5: 2, 2: 2, 8: 1}. - The second
foreachscans$arragain instead of iterating the count table, so the result follows original input order. - The second pass rejects
arr[0]=3,arr[1]=5,arr[2]=2,arr[3]=5, andarr[4]=3because each has count2. - At
arr[5],$valueis8and$count[$value] === 1, so the code prints8andbreaks before scanning the final2. echo $value . PHP_EOL;is the only output path in the checked run.
two-pass lookup
The first pass builds a frequency table. The second pass keeps the original order and stops at the first value with frequency one.