Use the same binary-search window as the iterative lesson, but pass lo and hi through recursive calls.

Algorithm

Basic Implementation

basic.lua
arr = {1, 3, 5, 7, 9, 11, 13}
target = 11
function search(lo, hi)
	if lo > hi then
		return -1
	end
	mid = lo + math.floor((hi - lo) / 2)
	value = arr[mid + 1]
	if value == target then
		return mid
	end
	if value < target then
		return search(mid + 1, hi)
	end
	return search(lo, mid - 1)
end
print(search(0, #arr - 1))

Complexity

  • Time: O(log n)
  • Space: O(log n) call stack

Implementation notes

  • Keep the explicit control flow. Library shortcuts would hide the state changes this lesson is meant to replay.
  • The final output is intentionally small and deterministic for cross-language comparison.
execution replay The checked-in replay follows the language-neutral state table for `search-binary-recursive`.
cross-language comparison This Lua DSA version keeps the same data and final output as every other DSA book in this wave.