Insert one value into a min-heap and restore the parent-child order by sifting upward.

Algorithm

@steps

  1. Store the heap in an array.
  2. Compare parent and child indexes instead of building explicit tree nodes.
  3. Swap only when the heap order is violated.
  4. Print the deterministic final heap state for replay comparison. @end @complexity
  • Time: O(log n)
  • Space: O(1) extra @end
sift up A new value starts at the end of the array and swaps with its parent while it is smaller.

Lua DSA Implementation

basic.lua
local function list_string(values) return "[" .. table.concat(values, ", ") .. "]" end
local function heap_insert(heap, value)
  table.insert(heap, value)
  local child = #heap
  while child > 1 do
    local parent = math.floor(child / 2)
    if heap[parent] <= heap[child] then break end
    heap[parent], heap[child] = heap[child], heap[parent]
    child = parent
  end
end
local function heap_pop(heap)
  local smallest = heap[1]
  heap[1] = table.remove(heap)
  local parent = 1
  while true do
    local left = parent * 2
    local right = left + 1
    if left > #heap then break end
    local child = left
    if right <= #heap and heap[right] < heap[left] then child = right end
    if heap[parent] <= heap[child] then break end
    heap[parent], heap[child] = heap[child], heap[parent]
    parent = child
  end
  return smallest
end
local heap = {2, 4, 7, 9, 6}
heap_insert(heap, 1)
print(list_string(heap))

@end @output [1, 4, 2, 9, 6, 7] @end