Graphs
Shortest Path (Unweighted, via BFS)
BFS explores a graph layer by layer, so the first time it reaches a vertex
is along a shortest path. Track dist[v] and parent[v] while exploring,
then walk parents back from the target to reconstruct the route.
Algorithm
On the canonical graph from graph-adjacency-list, the shortest path from
1 to 6 is [1, 2, 4, 5, 6] with distance 4. The path is rebuilt from
parent: 6 -> 5 -> 4 -> 2 -> 1, reversed.
layers equal distance
BFS order equals distance in an unweighted graph.
Basic Implementation
basic.lua
Replay: real traced execution (multi-file project)
local adj = {}
adj[1] = {2, 3}
adj[2] = {1, 4}
adj[3] = {1, 4}
adj[4] = {2, 3, 5}
adj[5] = {4, 6}
adj[6] = {5}
local src = 1
local dst = 6
local dist = {}
local parent = {}
dist[src] = 0
parent[src] = 0
local queue = {src}
local head = 1
while head <= #queue do
local v = queue[head]
head = head + 1
for i = 1, #adj[v] do
local nb = adj[v][i]
if dist[nb] == nil then
dist[nb] = dist[v] + 1
parent[nb] = v
queue[#queue + 1] = nb
end
end
end
local path = {}
local node = dst
while node ~= 0 do
path[#path + 1] = node
node = parent[node]
end
io.write("[")
for k = #path, 1, -1 do
if k < #path then io.write(", ") end
io.write(tostring(path[k]))
end
io.write("]\n")
io.write(tostring(dist[dst]) .. "\n")
dist ← {1: 0}
11local parent = {}12dist[src] = 013parent[src] = 0values this step{1: 0}distparent ← {1: null}
12dist[src] = 013parent[src] = 014local queue = {src}values this step{1: null}parentdist ← {1: 0, 2: 1, 3: 1}, parent ← {1: null, 2: 1, 3: 1}, queue ← [2, 3]
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1}dist{1: null, 2: 1, 3: 1}parent[2, 3]queue1dequeuedist ← {1: 0, 2: 1, 3: 1, 4: 2}, parent ← {1: null, 2: 1, 3: 1, 4: 2}
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1, 4: 2}dist{1: null, 2: 1, 3: 1, 4: 2}parent[3, 4]queue2dequeuedist ← {1: 0, 2: 1, 3: 1, 4: 2}, parent ← {1: null, 2: 1, 3: 1, 4: 2}
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1, 4: 2}dist{1: null, 2: 1, 3: 1, 4: 2}parent[4]queue3dequeuedist ← {1: 0, 2: 1, 3: 1, 4: 2, 5: 3}, parent ← {1: null, 2: 1, 3: 1, 4: 2, 5: 4}
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1, 4: 2, 5: 3}dist{1: null, 2: 1, 3: 1, 4: 2, 5: 4}parent[5]queue4dequeuedist ← {1: 0, 2: 1, 3: 1, 4: 2, 5: 3, 6: 4}, parent ← {1: null, 2: 1, 3: 1, 4: 2, 5: 4, 6: 5}
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1, 4: 2, 5: 3, 6: 4}dist{1: null, 2: 1, 3: 1, 4: 2, 5: 4, 6: 5}parent[6]queue5dequeuedist ← {1: 0, 2: 1, 3: 1, 4: 2, 5: 3, 6: 4}, parent ← {1: null, 2: 1, 3: 1, 4: 2, 5: 4, 6: 5}
16while head <= #queue do17 local v = queue[head]18 head = head + 1values this step{1: 0, 2: 1, 3: 1, 4: 2, 5: 3, 6: 4}dist{1: null, 2: 1, 3: 1, 4: 2, 5: 4, 6: 5}parent[]queue6dequeuepath ← [1, 2, 4, 5, 6]
33end34io.write("[")35for k = #path, 1, -1 dovalues this step[1, 2, 4, 5, 6]path{1: null, 2: 1, 3: 1, 4: 2, 5: 4, 6: 5}parentstdout ← [1, 2, 4, 5, 6]
38end39io.write("]\n")40io.write(tostring(dist[dst]) .. "\n")values this step[1, 2, 4, 5, 6]stdout[1, 2, 4, 5, 6]pathstdout ← 4
39io.write("]\n")40io.write(tostring(dist[dst]) .. "\n")values this step4stdout4dist[6]BFS path ← 1 -> 2 (1 edge, cost 10), cheaper weighted path ← 1 -> 3 -> 2 (2 edges, cost 2)
39io.write("]\n")40io.write(tostring(dist[dst]) .. "\n")values this step1 -> 2 (1 edge, cost 10)BFS path1 -> 3 -> 2 (2 edges, cost 2)cheaper weighted pathuse Dijkstra with a priority queueweighted algorithm1->2 weight 10, 1->3 weight 1, 3->2 weight 1edge weights
Complexity
- Time: O(V + E)
- Space: O(V)
Implementation notes
- Lua:
distdoubles as the visited check,parentrecords predecessors (0 marks the source), and a head index walks the queue table. - The replay shows
dist,parent, and the queue filling in, then the reconstructed path. It also contrasts that unweighted result with a weighted graph where Dijkstra with a priority queue is required.