Recursion and Dynamic Programming
Fibonacci with Memoization
Compute fib(n) recursively. Cache each fib(k) in a memo map so each
subproblem is solved at most once.
Algorithm
Canonical input n = 6 produces fib(6) = 8. Replay highlights every
memo write and every cache hit.
memoization
A table `memo` keyed by `n` stores each completed subproblem. Before recursing, check `memo[n] ~= nil`: a hit returns immediately, a miss descends.
explicit memo state
The memo is threaded through the recursion as the second parameter so the lesson stays about caching, not a closure upvalue.
Basic Implementation
basic.lua
Replay: real traced execution (multi-file project)
local function fib(n, memo)
if memo[n] ~= nil then
return memo[n]
end
if n < 2 then
memo[n] = n
return n
end
local value = fib(n - 1, memo) + fib(n - 2, memo)
memo[n] = value
return value
end
local memo = {}
local result = fib(6, memo)
print(result)
memo ← {}, action ← miss -> descend fib(5)
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{}memomiss -> descend fib(5)action6nmemo ← {}, action ← miss -> descend fib(4)
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{}memomiss -> descend fib(4)action5nmemo ← {}, action ← miss -> descend fib(3)
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{}memomiss -> descend fib(3)action4nmemo ← {}, action ← miss -> descend fib(2)
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{}memomiss -> descend fib(2)action3nmemo ← {}, action ← miss -> descend fib(1)
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{}memomiss -> descend fib(1)action2nmemo ← {1: 1}, action ← base 1; memo[1] = 1; return
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{1: 1}memobase 1; memo[1] = 1; returnaction1nmemo ← {0: 0, 1: 1}, action ← base 0; memo[0] = 0; fib(2)=1; memo[2] = 1
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{0: 0, 1: 1}memobase 0; memo[0] = 0; fib(2)=1; memo[2] = 1action0nmemo ← {0: 0, 1: 1, 2: 1, 3: 2}, action ← hit 1; fib(3)=2; memo[3] = 2
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{0: 0, 1: 1, 2: 1, 3: 2}memohit 1; fib(3)=2; memo[3] = 2action1nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3}, action ← hit 1; fib(4)=3; memo[4] = 3
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3}memohit 1; fib(4)=3; memo[4] = 3action2nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5}, action ← hit 2; fib(5)=5; memo[5] = 5
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5}memohit 2; fib(5)=5; memo[5] = 5action3nmemo ← {0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5, 6: 8}, action ← hit 3; fib(6)=8; memo[6] = 8
8end9local value = fib(n - 1, memo) + fib(n - 2, memo)10memo[n] = valuevalues this step{0: 0, 1: 1, 2: 1, 3: 2, 4: 3, 5: 5, 6: 8}memohit 3; fib(6)=8; memo[6] = 8action4nstdout ← 8
15local result = fib(6, memo)16print(result)values this step8stdout8result
Complexity
- Time: O(n) with memoization (vs. O(2^n) without)
- Space: O(n) memo + O(n) call stack
Implementation notes
- Lua: the recursion takes the memo as a parameter rather than as an upvalue or a module-level cache, which keeps state explicit without hiding the lesson behind a shared global. Tables pass by reference, so the recursive calls share the same memo without an explicit return-the-memo dance.
memo[n] ~= nilis the explicit cache-check predicate; Lua's table-default behaviour returnsnilfor absent keys, so the predicate stays parallel to the lesson spec instead of leaning on metatable defaults.- The replay shows the call stack on one side and the memo map on the other so memo writes and cache hits are visually distinct.