factorial(0) = 1, otherwise factorial(n) = n * factorial(n - 1). The smallest example of recursion with a single base case.

Algorithm

Canonical input n = 5 descends through six call frames and unwinds through five multiplications. Final result 120.

Basic Implementation

basic.kt
fun factorial(n: Int): Int {
	if (n == 0) {
		return 1
	}
	return n * factorial(n - 1)
}

fun main() {
	val result = factorial(5)
	println(result)
}

Complexity

  • Time: O(n)
  • Space: O(n) call stack

Implementation notes

  • Kotlin: same recursive shape as the other languages, with fun factorial(n: Int): Int documenting the integer contract.
  • The replay treats the call stack as a vertical list of frames; descent pushes, unwind pops with the computed multiplication shown.
base case `if (n == 0) return 1`
recursive call `n * factorial(n - 1)`