Linked Structures
Delete by Value
Find the node before the target value and rewire its next pointer so the target node leaves the chain.
Algorithm
The replay labels nodes by value, such as node(20), and never exposes object
identity or memory addresses. This Kotlin DSA implementation uses the
same small chain as the rest of the DSA track.
predecessor
Deletion needs the node before the one being removed.
rewiring
The predecessor skips the target and points at the target's next node.
Basic Implementation
basic.kt
Replay: real traced execution (multi-file project)
class Node(val value: Int, var next: Node? = null)
fun render(head: Node?): String {
val parts = mutableListOf<String>()
var cursor = head
while (cursor != null) {
parts.add(cursor.value.toString())
cursor = cursor.next
}
return parts.joinToString(" -> ") + " -> null"
}
fun main() {
val head = Node(10, Node(20, Node(30, Node(40))))
val target = 30
var cursor = head
while (cursor.next != null) {
if (cursor.next!!.value == target) {
cursor.next = cursor.next!!.next
break
}
cursor = cursor.next!!
}
println(render(head))
}
head ← 10 -> 20 -> 30 -> 40 -> null, target ← 30
1class Node(val value: Int, var next: Node? = null)values this step10 -> 20 -> 30 -> 40 -> nullhead30targetcursor ← node(20)
5var cursor = head6while (cursor != null) {7 parts.add(cursor.value.toString())values this stepnode(10) → node(20)cursorcursor.next ← node(40)
1class Node(val value: Int, var next: Node? = null)values this stepnode(30) → node(40)cursor.nextstdout ← 10 -> 20 -> 40 -> null
23 }24 println(render(head))25}values this step10 -> 20 -> 40 -> nullstdout10 -> 20 -> 40 -> nullhead
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Keep the explicit node and pointer/reference operations; array shortcuts hide the linked-list state this lesson is meant to replay.
- The final output prints the chain in a deterministic
a -> b -> nullform for cross-language comparison.