Arrays and Iteration
Find Maximum
Scan the array once, keeping the largest value seen so far. The replay highlights when a candidate replaces the running maximum.
Algorithm
execution replay
The checked-in replay follows the language-neutral state table for `array-find-max`.
cross-language comparison
This Kotlin DSA version keeps the same data and final output as every other DSA book in this wave.
Basic Implementation
basic.kt
Replay: real traced execution (multi-file project)
fun main() {
val arr = intArrayOf(3, 1, 4, 1, 5, 9, 2, 6)
var best = arr[0]
for (i in 1 until arr.size) {
if (arr[i] > best) {
best = arr[i]
}
}
println(best)
}
arr ← [3, 1, 4, 1, 5, 9, 2, 6], best ← 3
1fun main() {2 val arr = intArrayOf(3, 1, 4, 1, 5, 9, 2, 6)values this step[3, 1, 4, 1, 5, 9, 2, 6]arr3bestreplaced ← no
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this stepnoreplaced1i1arr[i]3bestbest ← 4, replaced ← yes
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this step3 → 4bestyesreplaced2i4arr[i]replaced ← no
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this stepnoreplaced3i1arr[i]4bestbest ← 5, replaced ← yes
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this step4 → 5bestyesreplaced4i5arr[i]best ← 9, replaced ← yes
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this step5 → 9bestyesreplaced5i9arr[i]replaced ← no
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this stepnoreplaced6i2arr[i]9bestreplaced ← no
4for (i in 1 until arr.size) {5 if (arr[i] > best) {6 best = arr[i]values this stepnoreplaced7i6arr[i]9beststdout ← 9
8 }9 println(best)10}values this step9stdout9best
Complexity
- Time: O(n)
- Space: O(1)
Implementation notes
- Kotlin stores the input as a primitive
IntArrayfromintArrayOf(3, 1, 4, 1, 5, 9, 2, 6), so indexed reads return non-nullIntvalues. arris aval, so the array reference is not rebound.bestis avarseeded fromarr[0]and is the only scalar state updated during the scan.- The loop uses
for (i in 1 until arr.size), visiting indexes1through7and avoiding a second read of the seed element at index0. if (arr[i] > best)performs a strictIntcomparison; equal values do not replace the current maximum.- The trace shows replacements at
i=2(3 -> 4),i=4(4 -> 5), andi=5(5 -> 9); indexes1,3,6, and7leavebestunchanged. println(best)uses Kotlin's standard output formatting for the finalInt, producing9.