Trees
Preorder Traversal
Visit the root before each subtree, producing root-left-right order.
Algorithm
The canonical tree is 4(2(1,3),6(5,7)), so this Java DSA
implementation can be compared directly with the rest of the DSA track.
Basic Implementation
Basic.java
import java.util.*;
public class Basic {
static class Node {
int value;
Node left;
Node right;
Node(int value) { this.value = value; }
Node(int value, Node left, Node right) { this.value = value; this.left = left; this.right = right; }
}
static String render(Node node) {
if (node == null) return "_";
if (node.left == null && node.right == null) return Integer.toString(node.value);
return node.value + "(" + render(node.left) + "," + render(node.right) + ")";
}
static Node sampleTree() {
return new Node(4, new Node(2, new Node(1), new Node(3)), new Node(6, new Node(5), new Node(7)));
}
static void preorder(Node node, List<Integer> output) { if (node == null) return; output.add(node.value); preorder(node.left, output); preorder(node.right, output); }
public static void main(String[] args) { List<Integer> output = new ArrayList<>(); preorder(sampleTree(), output); System.out.println(output); }
}
Complexity
- Time: O(n)
- Space: O(h) recursion stack
Implementation notes
- Render tree structure explicitly instead of printing node objects.
- The replay highlights the node, traversal state, queue, path, or search cursor that changes at each step.
preorder
Preorder records the current node before visiting left and right subtrees.