Find the first copy of a duplicated target by recording matches and continuing to search the left half.

Algorithm

Basic Implementation

Basic.java
public class Basic {
    public static void main(String[] args) {
        int[] arr = {1, 2, 4, 4, 4, 7, 9};
        int target = 4;
        int lo = 0;
        int hi = arr.length - 1;
        int result = -1;
        while (lo <= hi) {
            int mid = lo + (hi - lo) / 2;
            if (arr[mid] == target) {
                result = mid;
                hi = mid - 1;
            } else if (arr[mid] < target) {
                lo = mid + 1;
            } else {
                hi = mid - 1;
            }
        }
        System.out.println(result);
    }
}

Complexity

  • Time: O(log n)
  • Space: O(1)

Implementation notes

  • Keep the explicit control flow. Library shortcuts would hide the state changes this lesson is meant to replay.
  • The final output is intentionally small and deterministic for cross-language comparison.
execution replay The checked-in replay follows the language-neutral state table for `search-binary-first`.
cross-language comparison This Java DSA version keeps the same data and final output as every other DSA book in this wave.